[Clarification on Horizontal Angle to forward obstacles]

Hi Chris,

Thanks for clarifying. I'll try out my new understanding of the angle values and let you know if I have any further questions.

Best,

Thomas

[Meaning of Block Commands]

Where can I find the user guide? I was emailed a copy, but it seems incomplete.

[Clarification on Horizontal Angle to forward obstacles]

In the user guide it says that the return value of the horizontal angle is a normalized angle, which I understand to be a value between 0 and 1, but when i use "show log" to display the horizontal angle it seems to be in the range of -90 to 90.

Additionally, I was wondering if there are any resources in addition to the user guide, as it doesn't answer many of my questions.

Thanks in advance for your help!